Be yourself; Everyone else is already taken.
— Oscar Wilde.
This is the first post on my new blog. I’m just getting this new blog going, so stay tuned for more. Subscribe below to get notified when I post new updates.
Be yourself; Everyone else is already taken.
— Oscar Wilde.
This is the first post on my new blog. I’m just getting this new blog going, so stay tuned for more. Subscribe below to get notified when I post new updates.

Using higher-order functions will make your code:
var names = ["Jack", "Jecci", "Ram", "Tom"];
var upperCaseNames = [];
for(let i=0, totalNames = names.length; i< totalNames ; i= i +1) {
upperCaseNames[i] = names[i].toUpperCase();
}
var names = ["Jack", "Jecci", "Ram", "Tom"]; var upperCaseNames = names.map(name => name.toUpperCase());
Using loops
function print(name) {
console.log(name);
}
var names = ["Jack", "Jecci", "Ram", "Tom"];
for(let i=0, totalNames = names.length; i< totalNames ; i= i +1) {
print(names[i])
}
without loop
var names = ["Jack", "Jecci", "Ram", "Tom"]; names.forEach(name=> print(name));
Using normal for loop:
function isOdd(n) {
return n %2;
}
var numbers = [1,2,3,4,5];
var odd = [];
for(let i=0, total = numbers.length; i< total ; i= i +1) {
let number = numbers[i];
if( isOdd(number) ) {
odd.push(number);
}
}
Using filter:
var numbers = [1,2,3,4,5, 6, 7] var odd = numbers.filter(n => n%2); // single line
Sum of numbers:
var numbers = [1,2,3,4,5]
var result = 0;
for(let i=0, total = numbers.length; i< total ; i= i +1) {
result = result + numbers[i];
}
Using reduce:
var numbers = [1,2,3,4,5,6,7];
function sum(accumulator, currentValue){
return accumulator + currentValue;
}
var initialVal = 0;
var result = numbers.reduce(sum, initialVal);
The above code can be even more simplified:
var numbers = [1,2,3,4,5,6,7, 10]; var result = numbers.reduce((acc, val)=> acc+val, 0);
var names = ["ram", "raj", "rahul"];
for(let i=0, totalNames = names.length; i< totalNames ; i= i +1) {
if(names[i] === "rahul") {
console.log("%c found rahul", "color:red");
return;
}
}
Using some:
var names = ["ram", "raj", "rahul"];
let isRahulPresent = names.some(name => name==="rahul");
if(isRahulPresent) {
console.log("%c found rahul", "color:red");
}
Using for loop:
var num = [1,2,3,4,5, 0];
for(let i=0, total = numbers.length; i< total ; i= i +1) {
if(num <= 0) {
console.log("0 present in array");
}
}
Using every:
var num = [1,2,3,4,5, 0];
var isZeroFree = num.every(e => e > 0);
if(!isZeroFree) {
console.log("0 present in array");
}
Thanks for reading. I hope you like this.
⭐
Rating: 1 out of 5.